IS 4995 Part 21974AI Search Enabled✦ AI Generated

Criteria for Design of Reinforced Concrete Bins for Storage of Granular and Powdery Materials, Part II: Design Criteria

IS 4995 Part 2 (1974) provides comprehensive design criteria for reinforced concrete bins used to store granular and powdery materials. It covers circular, polygonal, and interstice bins, detailing structural design requirements including permissible stresses, load considerations, wall and bottom design, reinforcement specifications, and stability checks. This standard is essential for civil and structural engineers involved in designing storage bins for bulk materials such as foodgrains, cement, and fertilizers.

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What This Standard Covers

IS 4995 Part 2 (1974) provides comprehensive design criteria for reinforced concrete bins used to store granular and powdery materials. It covers circular, polygonal, and interstice bins, detailing structural design requirements including permissible stresses, load considerations, wall and bottom design, reinforcement specifications, and stability checks. This standard is essential for civil and structural engineers involved in designing storage bins for bulk materials such as foodgrains, cement, and fertilizers.

Who Uses This Standard

  • Structural Engineers
  • Civil Engineers
  • Design Consultants
  • Construction Engineers
  • Storage Facility Designers
  • Material Handling Engineers
  • Quality Control Engineers

Key Topics Covered

Design loads and load combinations for bins
Permissible stresses in concrete and steel reinforcement
Design of bin walls including hoop and meridional stresses
Design criteria for bin bottoms and hopper bottoms
Reinforcement detailing and permissible steel stresses
Structural stability under full and empty conditions
Design of ring girders supporting conical hoppers
Effects of shrinkage and temperature changes
Design considerations for interconnected polygonal and interstice bins
Openings and access provisions in bin walls
Foundation requirements for bin structures
Crack width control and durability provisions

Table of Contents

1Scope

Scope of IS 4995 Part 2 (Design Criteria for Circular Cement Storage Bins)

This standard provides the design parameters and notation for reinforced concrete circular bins storing bulk materials like cement.

Key Notations & Parameters:

SymbolMeaningUnit/Description
AHorizontal cross-sectional area of stored materialcm²
AcArea of columnscm²
ActConcrete area in tension per unit height of bin wallcm²/m
AsArea of reinforcement in bin wall at height under considerationcm²/m
AscArea of reinforcement in columncm²
DInternal diameter of circular binm
hHeight of bin wallm
tThickness of bin wallcm
Ec, EsModulus of elasticity of concrete and steelkg/cm² or MPa
PhHorizontal pressure on wall due to stored materialkN/m² or equivalent
MATMoment due to temperature difference across bin wallkNm or equivalent
WcrCrack width in bin wallmm
K1, K2, K3Coefficients for bending and torsional moments in ring girderDimensionless

Design Considerations:

  • Loads: Dead load, horizontal & vertical pressures, frictional forces.
  • Thermal effects: Temperature difference causing moments (MAT).
  • Reinforcement: Percentage and area of steel in walls and columns.
  • Safety factors: For concrete cracking and strength.
  • Thermal properties: Conductivity, surface conductance, and expansion coefficients.

Formula Examples:

  • Modular ratio:
    [ m = \frac{E_s}{E_c} ]

  • Percentage reinforcement:
    [ p = \frac{A_s}{A_c} \times 100 ]

  • Moment due to temperature difference:
    [ M_{AT} = \text{Function of } \Delta T, E_c, t, \text{and geometry} ]


flowchart LR
    A[Stored Material] -->|Horizontal Pressure Ph| B(Bin Wall)
2Definitions

IS 4995 Part 2: Key Definitions & Tables

Important Notations (Clause 3.1)

  • A = Horizontal cross-sectional area of stored material
  • Ac = Area of columns (cm²)
  • Act = Concrete area in tension per unit height of bin wall (cm²/m)
  • As = Area of reinforcement in bin wall at height (cm²/m)
  • Asc = Area of reinforcement in column (cm²)
  • D = Internal diameter of circular bin
  • Ec, Es = Modulus of elasticity of concrete and steel respectively
  • h = Height of bin wall
  • t = Thickness of bin wall
  • Wcr = Crack width in bin wall
  • Oct, Ocu = Permissible tensile and compressive strength of concrete

Crack Width Control (Clause 5.10.1 & 5.10.2.2)

  • Crack width satisfactory if bar diameters chosen per formula using factor β from Table 5.

Table 5: Values of β for Maximum Permissible Crack Width (mm)

Bar TypeSteel Stress σ<sub>sa</sub> (kg/cm²)β for 0.1 mm Crackβ for 0.2 mm Crack
Plain Bars1000 - 140065 - 35180 - 115
Deformed Bars1400 - 230065 - 10200 - 100

Table 4: Max Bar Diameters (mm) for No Crack Width Calculation

Bar TypeSteel Stress σ<sub>sg</sub> (kg/cm²)Max Diameter for 0.1 mm CrackMax Diameter for 0.2 mm Crack
Plain Bars1000 - 140014 - 630 - 18
Deformed Bars1400 - 230016 - 626 - 12

Notes:

  • Use **geometrical reinforcement % p₀
3General Requirements of Working Stress Method

IS 4995 Part 2: General Requirements of Working Stress Method

1. General Principles (Clause 5.1)

  • Design must consider all stress conditions per mechanics and sound engineering practice.
  • Monolithic construction effects on bending moments and shear forces must be accounted for.

2. Permissible Stresses in Steel Reinforcement (Clause 5.4.3, Table 2)

Stress TypeMild Steel (Grade I) kg/cm²Medium Tensile Steel kg/cm²High Yield Steel kg/cm²Welded Wire Fabric kg/cm²
Tension (up to 40 mm dia)1400Half guaranteed yield, max 1900--
Tension (over 40 mm dia)1300Half guaranteed yield, max 1900--
Tension in helical reinforcement100013001600-
Tension in shear reinforcement140014001750-
Compression in column bars130013001750-
Compression in beam/slab bars (with concrete resistance)Calculated concrete compressive stress × min(1.5 × modular ratio, Fsc)---
Compression in beam/slab bars (without concrete resistance)Half guaranteed yield, max 1900---

Notes:

  • For Grade II mild steel, permissible stresses = 90% of Grade I values.
  • Yield stress = 0.2% proof stress if no clear yield point.

3. Crack Width Control (Clause 5.10.2.2, Table 5)

Bar diameter selection for crack width control:

[ d \leq \frac{\Phi}{\sigma_{st}} ]

Where (\Phi) values depend on steel stress and max permissible crack width (0.1 mm or 0.2 mm).

Bar Type(\sigma_{st}) (kg/cm²)(\Phi) for 0.1 mm crack width(\Phi) for 0.2 mm crack width
4Materials and Construction Requirements

IS 4995 Part 2 (1974) — Materials & Construction Key Points

1. Notations (Clause 3.1)

  • A = Horizontal cross-sectional area of stored material
  • Ac = Area of columns (cm²)
  • As = Reinforcement area in bin wall (cm²/m)
  • Ec, Es = Modulus of elasticity of concrete and steel
  • D = Internal diameter of circular bin
  • t = Thickness of bin wall
  • Ph, Pp = Horizontal and vertical pressure from stored material
  • Wcr = Crack width in bin wall
  • Et = Thermal expansion coefficient of concrete
  • T, To, Ti = Temperatures inside/outside bin, material temperature

2. Permissible Stresses in Steel Reinforcement (Clause 5.4.3, Table 2)

Stress TypeMild Steel Bars (kg/cm²)Medium Tensile Steel Bars (kg/cm²)High Strength Steel Bars (kg/cm²)Welded Wire Fabric (kg/cm²)
Tension (≤40mm)1400Half yield, max 1900--
Tension (>40mm)1300Half yield, max 1900--
Tension in helical reinforcement100013001600-
Compression in column bars130013001750-
Compression in beam/slab (with concrete)Min(1.5mσ_c, σ_sc)---
  • Note: For mild steel Grade II (IS 432 Part I), permissible stresses = 90% of Grade I values or increase reinforcement by 10%.

3. Steel Types (Clause 4.2.2)

  • Mild steel or medium tensile steel bars per IS 432 (Part I & II)
  • Deformed bars per IS 1139
  • Cold twisted bars per IS 1786

Summary Diagram: Reinforcement & Stress Flow

graph TD
    A[Stored Material Pressure] -->|Horizontal (Ph),
5Design Criteria

IS 4995 Part 2 — Design Criteria: Key Points

  • Design Foundations as per relevant IS codes:
    • IS 456: Plain and Reinforced Concrete (latest edition recommended)
    • IS 1080: Code of Practice for Foundations in Soil
    • IS 2911 Part 1 & 3: Pile Foundations
    • IS 2950: Design of Foundations for Transmission Line Towers

Key Design Considerations:

  • Loadings: Self-weight, wind, seismic, and live loads as per IS 875 & IS 1893.
  • Soil Parameters: Bearing capacity, settlement criteria from site investigation.
  • Safety Factors: As specified in relevant IS codes for materials and load combinations.
  • Material Strengths: Use characteristic strengths per IS 456 and IS 2911.

Typical Foundation Design Formulae:

  • Safe Bearing Capacity (q_safe): [ q_{safe} = \frac{q_{ult}}{FS} ] where (q_{ult}) = ultimate bearing capacity, (FS) = factor of safety (usually 3).

  • Pile Capacity (Q): [ Q = Q_s + Q_b ] where (Q_s) = skin friction, (Q_b) = base resistance.

Summary Table: Design Codes for Foundations

AspectIS CodeNotes
Concrete DesignIS 456Reinforced concrete design
Soil BearingIS 1080Shallow foundations
Pile FoundationsIS 2911 (Part I & III)Pile design & load tests
Transmission Tower FoundationsIS 2950Special foundation design
flowchart TD
    A[Loadings] --> B[Foundation Design]
    B --> C[Soil Parameters]
    B --> D[Material Strength]
    B --> E[Safety Factors]
    C --> F[IS 1080, IS 2911]
    D --> G[IS 456]
    E --> H[Load Combinations IS 875]

Note: Always refer to the latest IS code editions for updated provisions.

5.1General Design Considerations

IS 4995 Part 2 (1974) – General Design Considerations: Key Formulas & Specifications

Key Notations:

  • A = Horizontal cross-sectional area of stored material
  • Ac = Area of columns (cm²)
  • Act = Concrete area in tension per unit height of bin wall (cm²/m)
  • As = Area of reinforcement in bin wall at height considered (cm²/m)
  • Ec, Es = Modulus of elasticity of concrete and steel
  • D = Internal diameter of circular bin
  • h = Height of bin wall
  • t = Thickness of bin wall
  • Ph = Horizontal pressure on wall due to stored material
  • Po = Vertical load on unit wall area due to friction
  • Wcr = Crack width in bin wall
  • K, K1, K2, K3 = Coefficients for bending and torsion moments in ring girder
  • Ar = Temperature difference across bin wall
  • Et = Coefficient of thermal expansion of concrete

Important Design Parameters:

  • Modular ratio:
    [ m = \frac{E_s}{E_c} ]
  • Pressure on wall:
    Horizontal pressure ( P_h ) and vertical pressure ( P_p ) must be calculated considering material properties and bin geometry.
  • Reinforcement percentage:
    [ p = \frac{A_s}{A_c} \times 100 ]
  • Thermal stresses:
    Moment due to temperature difference ( M_{AT} ) must be accounted for in design.

Design Checks:

  • Ensure crack width ( W_{cr} ) is within permissible limits.
  • Use safety factor ( K ) for concrete cracking.
  • Calculate bending moments using coefficients ( K_1, K_2 ) for ring girders.
  • Account for wall friction coefficients during filling and emptying.

Summary Table (Example):

ParameterSymbolUnitNotes
Bin wall thicknesstcmAs per design requirement
Internal diameterDmCircular bin diameter
Reinforcement areaAs
5.4Permissible Stresses

IS 4995 Part 2 - Permissible Stresses Summary


1. Permissible Stresses in Concrete (Table 1)

GradeCompression (kg/cm²)Shear (kg/cm²)Bond (kg/cm²)Bearing on Full Area (Plain) (kg/cm²)
M15050 (Bending), 40 (Direct)5.0 (Inclined Tension)Avg: 6.0, Local: 10.030
M20070, 507.08.0, 13.040
M25085, 608.09.0, 15.050
M300100, 809.010.0, 17.060
M350115, 9010.011.0, 18.070
M400130, 10011.012.0, 19.080

Note: Permissible tensile stress in bending = Permissible shear stress (inclined tension).


2. Permissible Stresses in Steel Reinforcement (Table 2)

Stress TypeMild Steel (Grade I)Cold Twisted BarsMedium Tensile Deformed BarsHigh Yield Strength SteelWelded Wire Fabric
Tension (up to 40 mm)1400 kg/cm²Half guaranteed yield (max 1900)---
Tension (over 40 mm)1300 kg/cm²Half guaranteed yield (max 1900)---
Tension in Helical Reinforcement (Compression member)100013001600--
Tension in Shear Reinforcement
5.5Design of Bin Walls

Design of Bin Walls as per IS 4995 Part 2

1. Walls of Polygonal Bins (Clause 5.5.2)

  • Consider walls as slabs spanning vertically/horizontally or two-way slabs for horizontal loads.
  • For vertical loads, design as beams with combined bending + axial forces.
  • Check for:
    • Vertical loads (stored material + frictional loads)
    • Horizontal loads (wind, seismic)
    • Temperature-induced bending moments
    • Restraints at top/bottom edges

2. Walls of Circular Bins (Clause 5.5.1)

  • Design primarily for hoop stresses due to internal pressure from stored material.
  • Use: [ \sigma_h = \frac{p \cdot r}{t} ] where:
    • ( \sigma_h ) = hoop stress
    • ( p ) = lateral pressure
    • ( r ) = radius of bin
    • ( t ) = wall thickness

3. Stability Checks (Clause 5.11)

  • Case a: Bin Full
    • Consider all vertical loads (including frictional wall load)
    • Lateral loads (wind or earthquake, whichever is critical)
  • Case b: Bin Empty
    • Consider vertical loads excluding stored material frictional load
    • Maximum lateral load (wind or earthquake)

Additional Notes:

  • For deep beams, refer to PCA curves (ST-66, 1951).
  • Always consider combined effects of bending, axial forces, temperature, and restraint.

flowchart TD
    A[Bin Walls] --> B{Type of Bin}
    B --> C[Circular Bin]
    B --> D[Polygonal Bin]
    C --> E[Design for Hoop Stress]
    D --> F[Design as Slabs/Beams]
    F --> G[Vertical Loads: Beam Action]
    F --> H[Horizontal Loads: Slab Action]
    A --> I[Stability Checks]
    I --> J[Full Bin: Vertical + Lateral Loads]
    I --> K[Empty Bin: Vertical (no friction) + Lateral Loads]

Summary: Design polygonal bin walls as beams/slabs with combined bending and axial

5.6Design of Ring Girders and Supports

Design of Ring Girders and Supports (IS 4995 Part 2, Clause 5.6)


Key Formulas (Clause 5.6.2)

For a ring girder simply supported on n equidistant columns:

  • Maximum negative bending moment at supports: [ M_{neg} = K_1 W_r ]

  • Maximum positive bending moment at mid-span: [ M_{pos} = K_2 W_r ]

  • Maximum torsional moment at angular distance (\theta) from support: [ T_{max} = K_3 W_r r ]

Where:

  • (W_r) = Total load on ring girder (including self-weight)
  • (r) = Mean radius of ring girder
  • (K_1, K_2, K_3) = Coefficients from Table 3
  • (\theta) = Angular distance from support (degrees)

Table 3: Coefficients for Ring Girder Moments

No. of SupportsMax Shear(K_1) (Neg. Moment)(K_2) (Pos. Moment)(K_3) (Torsion)(\theta) (Angular Distance)
3(W_r/6)0.06290.03330.013225° - 47'5"
4(W_r/8)0.03420.01760.005319° - 12'
5(W_r/10)0.02150.01070.002615° - 18.1'
6(W_r/12)0.01480.00750.001512° - 44'
...............
5.7Design of Bin Bottoms and Hopper Bottoms

Design of Bin Bottoms and Hopper Bottoms (IS 4995 Part 2)

1. Bin Bottom Design (Clause 5.7.1 & 5.7.1.1)

  • Vertical Load: As per 6.1.1.2 (a) & (b) of Part I; minimum load not less than 6.1.1.2(b).
  • Level Bottom: Treat as a horizontal slab monolithically cast with supporting structure.
  • Additional Loads: Include weight of conveying machinery + impact loads.

2. Ring Girder Design (Table 3)

  • For circular bins, bending and torsional moments are computed using coefficients (K_1, K_2, K_3) based on the number of supports.
No. of SupportsMax Shear(K_1)(K_2)(K_3)Angle (°-')
3(W/6)0.06290.03330.013225° 47.5'
4(W/8)0.03420.01760.005319° 12'
..................
12(W/24)0.00370.00180.00026° 20.8'
  • (W): Total vertical load on the ring girder.

3. Hopper Bottoms (Clause 5.7.2 & 5.7.2.4)

  • Design for loads in Clauses 5.3.0 and 5.7.2.1.
  • For non-standard shapes (sloping sides, special emptying), use mechanics principles and sound engineering judgment.

Summary Diagram: Load Path in Bin Bottom

graph TD
    Load[Vertical Load W]
    Conveying[Conveying Machinery Load + Impact]
    BinBottom
5.8Temperature Effects and Thermal Stresses

Temperature Effects and Thermal Stresses (IS 4995 Part 2)

Key Formula for Bending Moment due to Temperature Change (Clause 5.8.2):

[ M_{AT} = E_t \Delta T E_c I ]

  • (E_t = 11 \times 10^{-8} , / ^\circ C ) (Coefficient of thermal expansion of concrete)
  • (\Delta T) = Temperature difference (°C)
  • (E_c = 18000 \sqrt{f_{cu}} , \text{kg/cm}^2) (Modulus of elasticity of concrete)
  • (I) = Moment of inertia of bin wall section

Assumptions for Thermal Stresses (Clause 5.8):

  • Tensile strength of concrete is neglected.
  • Temperature variation is radial or horizontal only.
  • Effects of wind and elevation differences are neglected.

Calculating Thermal Stresses:

  • Compute bending moment (M_{AT}).
  • Apply mechanics of materials principles to find stresses in concrete and steel.
  • Add required reinforcement for thermal stresses to the bin walls.

Crack Width Control (Clause 5.10.2.2 & Table 5):

Type of BarSteel Stress ( \sigma_{sa} ) (kg/cm²) for Max Permissible Crack Width
0.1 mm
1000
Plain Bars65
Deformed Bars-

Summary:

  • Use (M_{AT} = E_t \Delta T E_c I) to find bending moments from temperature changes.
  • Neglect concrete tension; consider only radial/horizontal temperature gradients.
  • Calculate thermal stresses in steel and concrete from (M_{AT}).
  • Use Table 5 to select bar diameters to control crack widths.
flowchart
5.9Effects of Shrinkage

Effects of Shrinkage (IS 4995 Part 2 - Clauses 5.9 & related)

Key Points:

  • Shrinkage effect in concrete is equivalent to a temperature drop of 15℃ for structures with >0.5% reinforcement.
  • Shrinkage stresses are significant near edges with restraint; elsewhere, they can be ignored.
  • Additional vertical reinforcement is required near edges to resist shrinkage stresses.

Simplified Crack Width Check (Clauses 5.10.1 & 5.10.2.2)

  • Crack width control depends on bar diameter, steel stress, and bar type.
  • For reinforcement percentage ( p_0 \leq 0.4% ) and bar diameters below limits (Table 4), crack width checks may be waived.

Important Tables:

Table 4: Max Bar Diameters (mm) for No Crack Width Calculation

Bar TypeSteel Stress (\sigma_{og}) (kg/cm²)Max Bar Diameter (mm) for 0.1 mm CrackMax Bar Diameter (mm) for 0.2 mm Crack
Plain Bars1000 - 140014 - 630 - 18
Deformed Bars1400 - 230016 - 626 - 12

Table 5: Values of (\beta) for Crack Width Formula

Bar TypeSteel Stress (\sigma_{os}) (kg/cm²)(\beta) for 0.1 mm Crack(\beta) for 0.2 mm Crack
Plain Bars1000 - 140065 - 35180 - 115
Deformed Bars1400 - 230065 - 10200 - 100

Crack Width Formula (Clause 5.10.2.2)

[ d \leq \frac{\beta}{\sigma_{os}} ]

  • (d) = Bar diameter (mm)
  • (\beta) = Value from Table 5
5.10Crack Width Control

IS 4995 Part 2: Crack Width Control Key Points

1. Simplified Crack Width Check (Clause 5.10.2)

  • Applicable if:
    • Geometrical reinforcement % ( p_0 \leq 0.4% ) (Clause 5.10.1)
    • Bar diameters ≤ max values in Table 4

2. Table 4: Max Bar Diameters (mm) for No Crack Width Calculation

Bar TypeMax Diameter for 0.1 mm Crack Width (kg/cm²)Max Diameter for 0.2 mm Crack Width (kg/cm²)
10001400
Plain Bars146
Deformed Bars-16

3. For Other Cases (Clause 5.10.2.2)

  • Bar diameter (d) chosen by:

[ d \leq \frac{\phi}{\beta} ]

where (\beta) values are from Table 5.

4. Table 5: Values of (\beta) for Crack Width Control

Bar Type(\beta) for 0.1 mm Crack Width (kg/cm²)(\beta) for 0.2 mm Crack Width (kg/cm²)
10001400
Plain Bars6535
Deformed Bars-65

Summary:

  • Use **Table 4
5.11Stability Checks

IS 4995 Part 2 - Stability Checks (Clause 5.11)

Stability Check Loading Cases:

  • Case a) Bin Full:

    • Consider all vertical loads including frictional wall load.
    • Include lateral loads due to wind or earthquake (whichever governs).
  • Case b) Bin Empty:

    • Consider vertical loads excluding stored material frictional load.
    • Include maximum lateral load due to wind or earthquake.

Key Parameters & Notations (Clause 3.1):

SymbolMeaning
( P_h )Horizontal pressure on wall due to stored material
( P_o )Vertical load due to friction between material and bin wall
( W_s )Self weight of hopper bottom per unit area
( h )Height of bin wall
( t )Thickness of bin wall
( A_c )Area of columns (cm²)
( A_s )Area of reinforcement in bin wall (cm²/m)
( E_c, E_s )Modulus of elasticity of concrete and steel respectively
( m )Modular ratio ( = \frac{E_s}{E_c} )

Stability Check Formula (Typical):

[ \text{Factor of Safety (FS)} = \frac{\text{Resisting Moment or Force}}{\text{Applied Moment or Force}} \geq 1.5 \quad \text{(typical minimum)} ]

  • Calculate overturning moments due to lateral loads.
  • Calculate resisting moments from self-weight and vertical loads.
  • Check sliding using frictional resistance between bin base and foundation.

Crack Width Control (Clause 5.10.2.2):

Bar diameter ( \phi ) selection formula:

[ \phi = \frac{K}{\sigma_{sa}} ]

Where ( \sigma_{sa} ) = steel stress from Table 5, based on max permissible crack width (0.1 mm or 0.2 mm).


Tables Summary:

Table 5: Steel Stress ( \sigma_{sa} ) (kg/cm²) for permissible crack widths

Bar Type0.1 mm Crack Width0.2 mm Crack Width
Plain Bars
6Minimum Requirements

IS 4995 Part 2 (1974) — Minimum Requirements Summary

Key Notations (Clause 3.1)

  • A = Horizontal cross-sectional area of stored material
  • Ac = Area of columns (cm²)
  • As = Reinforcement area in bin wall (cm²/m)
  • Asc = Reinforcement area in column (cm²)
  • D = Internal diameter of circular bin
  • h = Height of bin wall
  • t = Thickness of bin wall
  • Ec, Es = Modulus of elasticity of concrete and steel
  • p₀ = Geometric percentage of tensile reinforcement in bin wall
  • Wcr = Crack width in bin wall
  • σ_oc, σ_cu = Permissible tensile and compressive strength of concrete

Crack Width Control (Clause 5.10.1 & Table 5.10.2)

  • Crack width checks can be simplified if:
    • Geometric reinforcement percentage p₀ ≤ 0.4%
    • Bar diameters ≤ values in Table 4 (below)
Bar TypeSteel Stress σ_gg (kg/cm²) for Max Crack WidthMax Bar Diameter (mm) for 0.1 mm CrackMax Bar Diameter (mm) for 0.2 mm Crack
100014001800
Plain Bars146-
Deformed Bars-1610

Important Formulae

  • Modular ratio:
    [ m = \frac{E_s}{E_c} ]

  • Geometric reinforcement percentage:
    [ p_0 = \frac{A_s}{A_{ct}} \times 100 ]

  • Crack width control:
    Use the above table to decide if detailed crack width calculations are necessary based on bar size and

Popular Questions About IS 4995 Part 2

?What are the permissible stresses for concrete and steel reinforcement in bin design according to IS 4995 Part 2?

According to IS 4995 Part 2 (1974) for reinforced concrete bins:

Permissible Stresses in Concrete (Table 1)

Concrete GradeCompression (kg/cm²)Shear (Inclined Tension) (kg/cm²)Tensile (Bending) (kg/cm²)Bond (kg/cm²)Bearing (Plain Concrete) (kg/cm²)
M150505.05.06.030
M200707.07.08.040
M250858.08.09.050
M3001009.09.010.060
M35011510.010.011.070
M40013011.011.012.080
  • Note: Tensile stress in bending = permissible shear stress (inclined tension).

Permissible Stresses in Steel Reinforcement (Table 2)

Stress TypeMild Steel (Grade I) (kg/cm²)Medium Tensile Steel (kg/cm²)High Tensile Steel (kg/cm²)Welded Wire Fabric (kg/cm²)
Tension (up to 40 mm dia)1400Half yield, max 1900--
Tension (over 40 mm dia)1300Half yield, max 1900--
Tension in helical reinforcement (compression member)100013001600-
Tension in shear reinforcement14001400
?How should the ring girder supporting a conical hopper be designed for bending and torsion?

Design of Ring Girder for Conical Hopper (IS 4995 Part 2)

According to Clauses 5.6.0 and 5.6.1:

  • The ring girder at the hopper-wall junction must resist axial force, bending, torsion, and shear.
  • Axial force = Horizontal component of inclined pull from the loaded hopper minus lateral thrust from stored material.
  • Design for the critical net horizontal force, considering:
    • Bin full condition
    • Material surface at ring level

From Clause 5.7.2.2 (conical hopper stresses):

  • The hopper induces meridional tension and hoop tension.

  • Hoop tension at any plane:

    [ T_h = P_n \times r \times \csc \alpha ]

    where:

    • (T_h) = hoop tension
    • (P_n) = normal design pressure at the plane
    • (r) = radius at the plane
    • (\alpha) = cone angle (slope angle)

Design steps:

  1. Calculate axial force on the ring girder.
  2. Determine bending moments from external loads and hopper geometry.
  3. Calculate torsion from asymmetrical loading or eccentricities.
  4. Design girder cross-section and reinforcement to resist combined axial, bending, and torsional stresses using interaction formulas.
  5. Ensure proper anchorage of meridional reinforcement into vertical walls for bond.

Summary Table

Load TypeSourceDesign Consideration
Axial ForceHorizontal component of hopper pull - lateral thrustUse critical net horizontal force
BendingExternal loads, hopper continuityCalculate bending moments
TorsionLoad eccentricity, asymmetryCalculate torsional moments
ShearLoad transferCheck shear capacity
Loading diagram...

This approach ensures the ring girder safely

?What load cases must be considered when checking the stability of reinforced concrete bins?

Load Cases for Stability Check of Reinforced Concrete Bins (IS 4995 Part 2, Clause 5.11):

  1. When Bin is Full:

    • Consider all vertical loads, including:
      • Self-weight of structure
      • Weight of stored material
      • Frictional wall load from stored material
    • Consider maximum lateral loads due to:
      • Wind or earthquake (whichever governs)
  2. When Bin is Empty:

    • Consider all vertical loads except the stored material load (i.e., exclude frictional wall load)
    • Consider maximum lateral loads due to wind or earthquake (whichever governs)

Additional Important Loading Conditions (Clause 5.3.0):

  • Dead load of structure
  • Superimposed loads (material handling machinery)
  • Bin loads as per Part I
  • Live load on roof (IS 875-1964)
  • Wind load (IS 875-1964)
  • Seismic load (IS 1893-1975)
  • Temperature effects
  • Shrinkage of concrete
  • Fixity effects at top/bottom edges

Summary Table:

Load CaseVertical Loads IncludedLateral Loads Included
Bin FullDead, live, stored material + frictionalWind or earthquake (max)
Bin EmptyDead, live (no stored material/frictional)Wind or earthquake (max)

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This ensures safety under critical load combinations per IS 4995 Part 2.

?How does the standard address the design of interconnected polygonal and interstice bins?

IS 4995 Part 2 addresses interconnected polygonal and interstice bins as follows:

  • Interconnected Polygonal Bins without Interstice (Clause 5.5.3.0):
    Design must consider the worst loading combinations of adjoining bins being full or empty, focusing on the junction walls where bins connect.

  • Interconnected Bins with One Interstice (Clause 5.5.3.1):
    Design walls for two critical cases:

    1. Interstice bin empty, adjoining main bins full
    2. Interstice bin full, adjoining main bins empty
  • Interstice Bin Definition (Clause 2.7):
    An interstice bin is the space enclosed between a battery of interconnected bins.

This ensures structural safety under varying load transfers at junctions and interstitial spaces.

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Summary: Design junction walls for worst-case load combinations considering full/empty states of interconnected bins and interstice bins.

?What are the requirements for openings and access points in bin walls to maintain structural integrity?

Requirements for Openings and Access Points in Bin Walls (IS 4995 Part 2)

While IS 4995 Part 2 does not explicitly detail openings in bin walls, the following principles apply based on clauses 5.11 and 5.5:

  • Structural Integrity: Openings must not compromise the bin wall’s ability to resist combined vertical (including frictional wall load) and lateral loads (wind/earthquake) under full and empty conditions (Clause 5.11).
  • Wall Behavior: Walls act as slabs or beams under loads (Clause 5.5.2). Openings reduce effective cross-section, so reinforcement around openings must be designed to handle bending, axial forces, and stress concentrations.
  • Reinforcement: Provide adequate vertical reinforcement around openings as per Clause 6.1.2:
    • Minimum vertical reinforcement: 0.2% of cross-section for single/exterior walls.
    • Preferably in two layers, spacing adjusted accordingly.
  • Design Approach: Treat walls with openings as deep beams or two-way slabs; use additional reinforcement or stiffeners around openings to maintain stability.

Summary Table:

ParameterRequirement
Load casesFull (vertical + lateral), Empty (lateral + self-weight)
Reinforcement (vertical)≥ 0.2% cross-section (single/exterior walls)
Reinforcement layeringPreferably two layers around openings
Opening designReinforce edges to resist bending & axial forces
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Note: Consult detailed structural analysis and possibly deep beam design curves (Portland Cement Association ST-66) for openings.

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